computer notes - Data Structures - 3

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computer notes - Data Structures - 24

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computer notes - Data Structures - 11

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The document discusses different ways to implement tables or dictionaries using data structures like arrays, linked lists, and skip lists. It explains that tables consist of rows and columns of data with fields/keys that uniquely identify each entry. Arrays allow fast searching if sorted but slow insertion/deletion. Linked lists allow fast insertion/deletion but slow searching. Skip lists combine fast search of sorted data structures with fast insertion/deletion of unsorted structures.

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The document discusses implementing a stack using a linked list as an alternative to an array. It explains that a linked list avoids size limitations of an array implementation. Elements can be inserted and removed from the start of the list in constant time, making it suitable for a stack. The four basic stack operations - push, pop, top, and isEmpty - can all be performed in constant time on this linked list implementation.

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The document discusses using trees and parent pointers to represent sets and solve the dynamic equivalence problem. Each element begins in its own set, represented as a tree with that element as the root. The union operation merges two trees by making one root point to the other. Find returns the root of the tree an element belongs to by traversing parent pointers up the tree. This can be optimized using a technique called union by rank to keep tree heights small.

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The document discusses different hashing techniques including linear probing, quadratic probing, and linked list chaining. It provides animations demonstrating how each technique handles collisions when storing data in an array. The document also discusses some common applications of hashing like symbol tables in compilers and spell checkers, as well as when hashing is most suitable compared to other data structures.

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The document discusses various aspects of balanced binary search trees, including: 1) Const keyword can be used to mark parameters and return values as constant to prevent unintended modification. 2) AVL trees are binary search trees where the heights of left and right subtrees differ by at most 1. 3) For a binary search tree to be balanced, the heights of left and right subtrees should be close to equal to avoid a skewed or degenerate tree structure.

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#ifndef LINKED_LIST_ #define LINKED_LIST_ template class LinkedList { private: std::shared_ptr> headPtr; // Pointer to first node in the chain; // (contains the first entry in the list) int itemCount; // Current count of list items std::shared_ptr> getNodeAt(int position) const; public: LinkedList(); LinkedList(const LinkedList& aList); virtual ~LinkedList(); bool isEmpty() const; int getLength() const; bool insert(int newPosition, const ItemType& newEntry); bool remove(int position); void clear(); /** throw PrecondViolatedExcept if position < 1 or position > getLength(). */ ItemType getEntry(int position) const throw(PrecondViolatedExcept); /** throw PrecondViolatedExcept if position < 1 or position > getLength(). */ void replace(int position, const ItemType& newEntry) throw(PrecondViolatedExcept); // Operator Overloading void operator = (const LinkedList& arg); friend std::ostream& operator << (std::ostream& os, const LinkedList& arg) { os << \"There are \" << arg.getLength() << \" values in the list:\" << std::endl; for (int i{ 1 }; i <= arg.getLength(); i++) { os << arg.getEntry(i) << std::endl; } os << std::endl << std::endl << std::endl << std::endl; return os; } }; // Returns a pointer to the Node at the given position. template std::shared_ptr> LinkedList::getNodeAt (int position) const { std::shared_ptr> currPtr{ headPtr }; for (int i{ 1 }; i < position; i++) currPtr = currPtr->getNext(); return currPtr; } // Default constructor. template LinkedList::LinkedList() { headPtr = nullptr; itemCount = 0; } // Copy constructor. template LinkedList::LinkedList(const LinkedList& aList) { itemCount = aList.getLength(); auto currPtr{ aList.headPtr }; auto newNodePtr{ headPtr = std::make_shared>(currPtr->getItem()) }; auto prevNodePtr{ newNodePtr }; currPtr = currPtr->getNext(); for (int i{ 2 }; i <= itemCount; i++) { newNodePtr = std::make_shared>(currPtr->getItem()); prevNodePtr->setNext(newNodePtr); prevNodePtr = newNodePtr; currPtr = currPtr->getNext(); } } // Destructor. template LinkedList::~LinkedList() { headPtr = nullptr; itemCount = 0; } // Accessor/Info Functions. template bool LinkedList::isEmpty() const { return (itemCount > 0)?0:1; } template int LinkedList::getLength() const { return itemCount; } // Places a Node at a given position (element at the same position is now pos+1). template bool LinkedList::insert(const int newPosition, const ItemType& newEntry) { bool ableToInsert{ (newPosition >= 1) && (newPosition <= itemCount + 1) }; if (ableToInsert) { // Create a new node containing the new entry auto newNodePtr{ std::make_shared>(newEntry) }; // Attach new node to chain if (newPosition == 1) { // Insert new node at beginning of chain newNodePtr->setNext(headPtr); headPtr = newNodePtr; } else { // Find node that will be before new node auto prevPtr{ getNodeAt(newPosition - 1) }; // Insert new node after node to which prevPtr points newNodePtr->setNext(prevPtr->getNext()); prevPtr->setNext(newNodePtr); } // end if itemCount++; // .

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ItemNode.h: #include <iostream> #include <string> using namespace std; class ItemNode { private: string item; ItemNode* nextNodeRef; public: // Constructor ItemNode() { item = ""; nextNodeRef = NULL; } // Constructor ItemNode(string itemInit) { this->item = itemInit; this->nextNodeRef = NULL; } // Constructor ItemNode(string itemInit, ItemNode *nextLoc) { this->item = itemInit; this->nextNodeRef = nextLoc; } // Insert node after this node. void InsertAfter(ItemNode &nodeLoc) { ItemNode* tmpNext; tmpNext = this->nextNodeRef; this->nextNodeRef = &nodeLoc; nodeLoc.nextNodeRef = tmpNext; } // Define InsertAtEnd() function that inserts a node // to the end of the linked list void InsertAtEnd(string item) { ItemNode* newNode = new ItemNode(item); if (nextNodeRef == NULL) { nextNodeRef = newNode; } else { ItemNode* current = nextNodeRef; while (current->nextNodeRef != NULL) { current = current->nextNodeRef; } current->nextNodeRef = newNode; } } // Get location pointed by nextNodeRef ItemNode* GetNext() { return this->nextNodeRef; } void PrintNodeData() { cout << this->item << endl; } }; int main() { int numItems; cin >> numItems; ItemNode head; ItemNode* current = &head; for (int i = 0; i < numItems; i++) { string item; cin >> item; current->InsertAtEnd(item); current = current->GetNext(); } current = head.GetNext(); while (current != NULL) { current->PrintNodeData(); current = current->GetNext(); } return 0; } main.cpp (only for viewing) #include "ItemNode.h" int main() { ItemNode *headNode; // Create intNode objects ItemNode *currNode; ItemNode *lastNode; string item; int i; int input; // Front of nodes list headNode = new ItemNode(); lastNode = headNode; cin >> input; for (i = 0; i < input; i++) { cin >> item; currNode = new ItemNode(item); lastNode->InsertAtEnd(currNode); lastNode = currNode; } // Print linked list currNode = headNode->GetNext(); while (currNode != NULL) { currNode->PrintNodeData(); currNode = currNode->GetNext(); } } in c++ please. Thank you! 18.18 LAB: Grocery shopping list (linked list: inserting at the end of a list) Given main0, define an InsertAtEnd() member function in the ItemNode class that adds an element to the end of a linked list. DO NOT print the dummy head node. Ex. if the input is: begin{tabular}{|l} hline 4 Kale Lettuce Carrots Peanuts end{tabular} where 4 is the number of items to be inserted; Kale, Lettuce, Carrots, Peanuts are the names of the items to be added at the end of the list. The output is:.

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feroz544

could you implement this function please, im having issues with it. void makeList (const ListNode::value_type [],const size_t& count) class ListNode { public: typedef int value_type; ListNode (value_type d = value_type(), ListNode* n = NULL) { datum = d; next = n; } //Assessor value_type getDatum () const { return datum; } ListNode const* getNext () const { return next; } //Mutator void setDatum (const value_type& d) {datum = d; } ListNode* getNext () { return next; } void setNext (ListNode* new_link) {next = new_link; } private: value_type datum; ListNode* next; }; class LinkedList { public: LinkedList (); virtual ~LinkedList (); void insertItem (ListNode::value_type); void makeList (const ListNode::value_type [],const size_t& count); void deleteList (); //The following friend function is implemented in lablinklist.cpp friend std::ostream& operator<<(std::ostream&, const LinkedList&); private: ListNode* head; }; This is the pseudocode, but i still have a hard time undertanding it. Creating a List (makeList(const ListNode::value_type [],const size_t& count)) This function receives an array in the order that we want to add it to the linkedlist. Index 0 will be the head node, index n will be the last node. First, create a node initialized with a data value and a NULL pointer. Set the \"head\" to point to the first node. Set up a current-pointer to the first node (or \"head\"). Get a data value for the next node. While more nodes to add { Create a new node initialized with the data value and a NULL pointer. Set the current-pointer link member (\"next\") to the new node. Set the current-pointer to point to the new node. Get a data value for the next node. } Thanks. Solution //linkedList.h #ifndef LINKEDLIST_H #define LINKEDLIST_H #include #include class ListNode { public: typedef int value_type; ListNode(value_type d = value_type(), ListNode* n = NULL) { datum = d; next = n; } //Assessor value_type getDatum() const { return datum; } ListNode const* getNext() const { return next; } //Mutator void setDatum(const value_type& d) { datum = d; } ListNode* getNext() { return next; } void setNext(ListNode* new_link) { next = new_link; } private: value_type datum; ListNode* next; }; class LinkedList { public: LinkedList(); virtual ~LinkedList(); void insertItem(ListNode::value_type); void makeList(const ListNode::value_type[], const size_t& count); void deleteList(); //The following friend function is implemented in lablinklist.cpp friend std::ostream& operator<<(std::ostream&, const LinkedList&); private: ListNode* head; }; #endif ------------------------------------------------------------- //linkedList.cpp #include \"linkedlist.h\" LinkedList::LinkedList() { head = NULL; } LinkedList::~LinkedList() { ListNode *tmp = head; while (tmp != NULL) { head = head->getNext(); delete tmp; tmp = head; } } void LinkedList::insertItem(ListNode::value_type item) { ListNode *newNode,*cur = head; newNode = new ListNode; newNode->setDatum(item); newNode->setNext(NULL);.

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hi i have to write a java program involving link lists. i have a problem with the nodes, as it is posting errors with the nodes. please help me with this problem. thank you. public class LinkLists { /* only need to store a single pointer to the node at the head * of the list. * The pointer is null if the list is empty. * Also record the size of the list. */ protected Node head; /* invariant: size is the number of nodes in the list pointed to by head */ protected int size; /* no-arguments default constructor creates an empty list */ public LinkLists() { head = null; // start with an empty list size = 0; } /* accessor method */ public int size() { return size; } /* value to add to the end of the list */ public void add(T value) { head = addAtEnd(head, value); size++; } /* node of the list to which the value should be added * value to add to the end of the list */ private Node addAtEnd(Node node, T value) { if (node == null) { // special case return new Node(value, null); } else if (node.getNext() == null) { // other special case node.setNext(new Node(value, null)); } else { addAtEnd(node.getNext(), value); } return node; } /* iterative implementation of the same method * value to add to the end of the list */ public void add2(T value) { if (head == null) { head = new Node(value, null); } else { Node node = head; // guaranteed not to be null initially while (node.getNext() != null) { node = node.getNext(); // guaranteed not to be null here } // now, node.getNext() is guaranteed to be null // similar to the second special case in addAtEnd node.setNext(new Node(value, null)); } size++; } public void remove(int position) throws BadItemCountException { if ((position < 1) || (position > size)) { throw new BadItemCountException(\"invalid position \" + position + \", only 1..\" + size + \" available\"); } if (position == 1) { head = head.getNext(); } else { Node node = head; for (int i = 2; i < position; i++) { node = node.getNext(); } node.setNext(node.getNext().getNext()); } size--; // one less item } public String toString() { return toString(head); } private String toString(Node node) { if (node == null) { return \"\"; } else { return node.getValue() + \"\ \" + toString(node.getNext()); } } public static void main(String[] args) { /* create two empty lists, make sure they print out correctly */ LinkLists list1 = new LinkLists(); LinkLists list2 = new LinkLists(); System.out.println(\"list1 = \'\" + list1 + \"\', list2 = \'\" + list2 + \"\'\"); System.out.println(\"list1.size() = \" + list1.size() + \", list2.size() = \" + list2.size()); /* insert some items, keep checking */ list1.add(\"hello\"); list1.add(\"world\"); list2.add(\"foo\"); list2.add(\"bar\"); list2.add(\"baz\"); System.out.println(\"list1 = \'\" + list1 + \"\', list2 = \'\" + list2 + \"\'\"); System.out.println(\"list1.size() = \" + list1.size() + \", list2.size() = \" + list2.size()); /* remove an item at an invalid position */ boolean caught = false; try { list2.remove(4); } catch .

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This assignment and the next (#5) involve design and development of a sequential non contiguous and dynamic datastructure called LinkedList. A linked list object is a container consisting of connected ListNode objects. As before, we are not going to use pre-fabricated classes from the c++ library, but construct the LinkedList ADT from scratch. The first step is construction and testing of the ListNode class. A ListNode object contains a data field and a pointer to the next ListNode object (note the recursive definition). #This assignment requires you to 1. Read the Assignment 4 Notes 2. Watch the Assignment 4 Support video 3. Implement the following methods of the ListNode class -custom constructor -setters for next pointer and data 4. Implement the insert and remove method in the main program 5. Scan the given template to find the above //TODO and implement the code needed //TODO in ListNodecpp.h file public: ListNode(T idata, ListNode<T> * newNext); public: void setNext(ListNode<T> * newNext); public: void setData(T newData); // TODO in main program void remove(ListNode<int> * &front,int value) void insert(ListNode<int> * &front,int value) # The driver is given ListNodeMain.cpp is given to you that does the following tests 1. Declares a pointer called front to point to a ListNode of datatype integer 2. Constructs four ListNodes with data 1,2,4 and adds them to form a linked list. 3. Inserts ListNode with data 3 to the list 4. Removes node 1 and adds it back to test removing and adding the first element 5. Removes node 3 to test removing a middle node 6. Removes node 4 to test removing the last node 7. Attempt to remove a non existent node 8. Remove all existing nodes to empty the list 9. Insert node 4 and then node 1 to test if insertions preserve order 10.Print the list Main.cpp #include <iostream> #include "ListNodecpp.h" // REMEMBER each ListNode has two parts : a data field // and an address field. The address is either null or points to the next node //in the chain //Requires: integer value for searching, address of front //Effects: traverses the list node chain starting from front until the end comparing search value with listnode getData. Returns the original search value if found, if not adds +1 to indicate not found //Modifies: Nothing int search(ListNode<int> * front, int value); //Requires: integer value for inserting, address of front //Effects: creates a new ListNode with value and inserts in proper position (increasing order)in the chain. If chain is empty, adds to the beginning //Modifies: front, if node is added at the beginning. //Also changes the next pointer of the previous node to point to the //newly inserted list node. the next pointer of the newly inserted pointer //points to what was the next of the previous node. //This way both previous and current links are adjusted //******** NOTE the use of & in passing pointer to front as parameter - // Why do you think this is needed ?********** void insert(ListNode<int> * &fr.

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Here is the editable codeSolutionimport java.util.NoSuchEleme.pdf

arrowmobile

Here is the editable code: Solution import java.util.NoSuchElementException; public class DoublyLinkedListImpl { private Node head; private Node tail; private int size; public DoublyLinkedListImpl() { size = 0; } private class Node { E element; Node next; Node prev; public Node(E element, Node next, Node prev) { this.element = element; this.next = next; this.prev = prev; } } public int size() { return size; } public boolean isEmpty() { return size == 0; } public void addFirst(E element) { Node tmp = new Node(element, head, null); if(head != null ) {head.prev = tmp;} head = tmp; if(tail == null) { tail = tmp;} size++; System.out.println(\"adding: \"+element); } /** * adds element at the end of the linked list * @param element */ public void addLast(E element) { Node tmp = new Node(element, null, tail); if(tail != null) {tail.next = tmp;} tail = tmp; if(head == null) { head = tmp;} size++; System.out.println(\"adding: \"+element); } public void iterateForward(){ System.out.println(\"iterating forward..\"); Node tmp = head; while(tmp != null){ System.out.println(tmp.element); tmp = tmp.next; } } /** * this method walks backward through the linked list */ public void iterateBackward(){ System.out.println(\"iterating backword..\"); Node tmp = tail; while(tmp != null){ System.out.println(tmp.element); tmp = tmp.prev; } } public E removeFirst() { if (size == 0) throw new NoSuchElementException(); Node tmp = head; head = head.next; head.prev = null; size--; System.out.println(\"deleted: \"+tmp.element); return tmp.element; } public E removeLast() { if (size == 0) throw new NoSuchElementException(); Node tmp = tail; tail = tail.prev; tail.next = null; size--; System.out.println(\"deleted: \"+tmp.element); return tmp.element; } public static void main(String a[]){ DoublyLinkedListImpl dll = new DoublyLinkedListImpl(); dll.addFirst(10); dll.addFirst(34); dll.addLast(56); dll.addLast(364); dll.iterateForward(); dll.removeFirst(); dll.removeLast(); dll.iterateBackward(); } } import java.util.Scanner; /* Class Node */ class Node { protected int data; protected Node next, prev; /* Constructor */ public Node() { next = null; prev = null; data = 0; } /* Constructor */ public Node(int d, Node n, Node p) { data = d; next = n; prev = p; } /* Function to set link to next node */ public void setLinkNext(Node n) { next = n; } /* Function to set link to previous node */ public void setLinkPrev(Node p) { prev = p; } /* Funtion to get link to next node */ public Node getLinkNext() { return next; } /* Function to get link to previous node */ public Node getLinkPrev() { return prev; } /* Function to set data to node */ public void setData(int d) { data = d; } /* Function to get data from node */ public int getData() { return data; } } /* Class linkedList */ class linkedList { protected Node start; protected Node end ; public int size; /* Constructor */ public linkedList() { start = null; end = null; size = 0; } /* Function to check if list is empty */ public boolean isE.

Doublylinklist

ritu1806

This document presents information on doubly linked lists including their representation, initialization, node creation, and various operations like insertion, deletion, and traversal. It discusses inserting and deleting nodes at the beginning or end of the list, as well as inserting before or after a specified node. Code examples are provided for initializing a doubly linked list and performing each operation.

Can you please debug this Thank you in advance! This program is sup.pdf

FashionBoutiquedelhi

Can you please debug this? Thank you in advance! This program is supposed to use stacks and find the paths of an airplane. It should tell you whether or not the plane goes from the requested city to the requested destination. requestFile.txt contains the requests, flightFile.txt contains the flights and cityFile.txt contains the city\'s that the airline serves. My errors: my output is simply \"Hpair does not serve Los Angeles.\" Thats it and it stops. It should look something like (these are not real values of the file just an example): \"Request is to fly from cityA to CityB. Hpair flight from cityA to CityB. Request is to fly from cityC to cityD. Sorry, HPAir does not serve City D Request is to fly from cityE to CityF Sorry, HPAir does not fly from cityE to CityF\" **It said to use ispath.cpp but I got confused on how to implement it completely.\" isPath.cpp //***I did not include ispath.cpp in my program. Parts of it are in the map.h portion. main.cpp #include #include #include \"Map.h\" using namespace std; int main() { Map aMap; aMap.readFlights(); aMap.verifyRequestedFile(); } StackInterface.h #ifndef StackInterface_h #define StackInterface_h template class StackInterface { /** Checks if the stack is empty. @return True if the stack is empty or false if the stack is not.*/ virtual bool isEmpty() const = 0; /** Adds a new item to the stack @post newEntry is at the top of the stack @param newEntry is the object to be added to the stack @return True if successfully added, otherwise false. */ virtual bool push(const ItemType& newEntry) = 0; /** Removes item from stack @post The top item in the stack is removed @return True if the item was removed, false if it was not. */ virtual bool pop() = 0; /** Returns the top item in the stack @pre The stack is not empty @post The top item in the stack is returned @return The top of the stack */ virtual ItemType peek() const = 0; }; #endif /* StackInterface_h */ Node.h #ifndef node_h #define node_h template class Node { public: Node(); Node (const ItemType &anItem); Node(const ItemType &anItem, Node * nextNodePtr); void setItem(const ItemType &anItem); void setNext(Node * nextNodePtr); ItemType getItem() const; Node* getNext() const; private: ItemType item; Node* next; }; template Node::Node():next(nullptr){} template Node::Node(const ItemType &anItem):item(anItem), next(nullptr){} template Node::Node(const ItemType &anItem, Node * nextNodePtr):item(anItem), next(nextNodePtr) { } template void Node::setItem(const ItemType &anItem){ item = anItem; } template void Node::setNext(Node * nextNodePtr) { next = nextNodePtr; } template ItemType Node::getItem() const { return item; } template Node* Node::getNext()const{ return next; } #endif /* node_h */ LinkedStack.h #include #ifndef LinkedStack_h #define LinkedStack_h #include \"Node.h\" #include \"StackInterface.h\" template class LinkedStack:public StackInterface{ public: LinkedStack(); LinkedStack(const LinkedStack &aStack); //space matter?*********** virt.

Rewrite this code so it can use a generic type instead of integers. .pdf

alphaagenciesindia

Rewrite this code so it can use a generic type instead of integers. This means we can use any data type with it. For example: LinkedList = new LinkedLIst<>(); public class Main { public static void main(String[] args) { /* * Expected output: * * The list: 8 -> 1 -> 5 -> 3 -> 6 * Size: 5 * Head: 8 * Tail: 6 * Removeing 1... * The list: 8 -> 5 -> 3 -> 6 * Size: 4 * Head: 8 * Tail: 6 * Removeing head... * The list: 5 -> 3 -> 6 * Size: 3 * Head: 5 * Tail: 6 * Removeing tail... * The list: 5 -> 3 * Size: 2 * Head: 5 * Tail: 3 */ LinkedList list = new LinkedList(); list.append(5); list.append(3); list.append(6); list.prepend(1); list.prepend(8); printListDetails(list); System.out.println("Removeing 1..."); list.removeByValue(1); printListDetails(list); System.out.println("Removeing head..."); list.removeHead(); printListDetails(list); System.out.println("Removeing tail..."); list.removeTail(); printListDetails(list); } public static void printListDetails(LinkedList list) { System.out.println("The list: " + list.toString()); System.out.println("Size: " + list.size()); System.out.println("Head: " + list.getHead()); System.out.println("Tail: " + list.getTail()); } } ________________________________________ public class LinkedList { private Node head; private Node tail; private int size; public LinkedList() { head = null; tail = null; size = 0; } public void append(int data) { Node newNode = new Node(data); if (head == null) { head = newNode; } else { tail.next = newNode; } tail = newNode; size++; } public void prepend(int data) { Node newNode = new Node(data); if (head == null) { head = newNode; tail = newNode; } else { newNode.next = head; head = newNode; } size++; } public int getHead() { return head.data; } public int getTail() { return tail.data; } public int size() { return size; } public void removeByValue(int data) { Node current = head; while (current.next != null && current.next.data != data) { current = current.next; } if (current.next != null) { current.next = current.next.next; size--; if (current.next == null) { tail = current; } } } public int removeHead() { int removedData = head.data; head = head.next; size--; if (head == null) { tail = null; } return removedData; } public int removeTail() { int removedData = tail.data; if (head == tail) { head = null; tail = null; } else { Node current = head; while (current.next != tail) { current = current.next; } tail = current; tail.next = null; } size--; return removedData; } @Override public String toString() { StringBuilder builder = new StringBuilder(); Node current = head; while (current != null) { builder.append(current.data); if (current.next != null) { builder.append(" -> "); } current = current.next; } return builder.toString(); } private class Node { public Node next; public int data; public Node(int data) { this.data = data; } } }.

Doubly linklist

ilsamaryum

This C++ code defines a doubly linked list data structure. It includes a node class with data, previous, and next pointers. The doubly linked list class contains functions to add nodes to the beginning or end of the list, add a node after a specified location, delete a node, display all nodes, count the total nodes, and destroy the list. The main function contains a menu to test the doubly linked list functions by adding, deleting, displaying, and counting nodes.

lab08build.bat@echo offclsset DRIVE_LETTER=1s.docx

DIPESH30

lab08/build.bat @echo off cls set DRIVE_LETTER=%1: set PATH=%DRIVE_LETTER%\MinGW\bin;%DRIVE_LETTER%\MinGW\msys\1.0\bin;%DRIVE_LETTER%\MinGW\gtkmm3\bin;%DRIVE_LETTER%\MinGW\gtk\bin;c:\Windows;c:\Windows\system32 set PROJECT_PATH=. make DRIVE_LETTER="%DRIVE_LETTER%" PROJECT_DIR="%PROJECT_PATH%" lab08/CSC2110/CD.h #if !defined CD_H #define CD_H #include "Song.h" #include "Text.h" using CSC2110::String; #include "ListArray.h" using CSC2110::ListArray; namespace CSC2110 { class CD { private: String* artist; String* title; int year; int rating; int num_tracks; ListArray<Song>* songs; public: CD(String* artist, String* title, int year, int rating, int num_tracks); virtual ~CD(); String* getKey(); void addSong(String* title, String* length); void displayCD(); static ListArray<CD>* readCDs(const char* file_name); static int compare_items(CD* one, CD* two); static int compare_keys(String* sk, CD* cd); static char getRadixChar(CD* cd, int index); //1-based }; } #endif lab08/CSC2110/Double.h #if !defined (DOUBLE_H) #define DOUBLE_H namespace CSC2110 { class Double { private: double value; public: Double(double val); ~Double(); double getValue(); }; } #endif lab08/CSC2110/HighPerformanceCounter.h #if !defined (HIGHPERFORMANCECOUNTER_H) #define HIGHPERFORMANCECOUNTER_H namespace CSC2110 { class HighPerformanceCounter { private: double micro_spt; //micro_seconds per tick HighPerformanceCounter(); static HighPerformanceCounter* hpc; static int getTicksPerSecond(); public: virtual ~HighPerformanceCounter(); static HighPerformanceCounter* getHighPerformanceCounter(); int getCurrentTimeInTicks(); double getTimeDifferenceInMicroSeconds(int start_time, int end_time); }; } #endif lab08/CSC2110/Integer.h #if !defined (INTEGER_H) #define INTEGER_H namespace CSC2110 { class Integer { private: int value; public: Integer(int val); virtual ~Integer(); int getValue(); }; } #endif lab08/CSC2110/Keyboard.h #if !defined KEYBOARD_H #define KEYBOARD_H #include "Text.h" using CSC2110::String; #include <string> using namespace std; namespace CSC2110 { class Keyboard { private: Keyboard(); public: virtual ~Keyboard(); static Keyboard* getKeyboard(); //pre: the string (character literal) that will prompt the user for input //post: the input read from the keyboard interpreted as an int is returned int readInt(string prompt); int getValidatedInt(string prompt, int min, int max); //pre: the string that will prompt the user for input //post: the input read from the keyboard interpreted as a double is returned double readDouble(string prompt); double getValidatedDouble(string prom ...

So I have this code(StackInAllSocks) and I implemented the method but.pdf

aksahnan

So I have this code( StackInAllSocks ) and I implemented the method but I can't seem to figure out why there isn't anything showing up on the console. It should pop,peek and push b using the methods from the class called ArrayListTen . The ArrayListTen works fine and compiles the tested code of Rigth# but for StackInAllSocks it doesn't complete at all. note that file VodeDodeis not to be changed is just a Node storage area of the array list. Did I implement the method on StackInAllSocks correctly? if so, should I not use the method from the ArrayListTen .? __________________________________________________________________________ : the code is : VodeDodeis class VodeDode<T> { private T data; private VodeDode<T> next; private VodeDode<T> prev; public VodeDode(T data) { this.data = data; this.next = null; this.prev = null;} public T getData() { return data;} public void setData(T data) { this.data = data;} public VodeDode<T> getNext() { return this.next;} public void setNext(VodeDode<T> next) { this.next = next;} public VodeDode<T> getPrev() { return this.prev;} public void setPrev(VodeDode<T> prev) { this.prev = prev;} @Override public String toString() { return data.toString();}} _________________________________________________________________________ CODE that works fine called ArrayListTen: import java.util.Iterator; public class ArrayListTen<T> implements Iterable<T> { private VodeDode<T> head; //beginning of list private VodeDode<T> tail; //end of list private int size; private VodeDode<T> new_item; public ArrayListTen( ){ this.head = null; this.tail = null; this.size = 0;} public int lenght() { return size ;} public T getBegin() { if (this.head != null) { return head.getData();} else { return null;}} public void addBegin(T value) { VodeDode<T> newVodeDode =new VodeDode<T>(value); if (this.head== null) { head = newVodeDode; tail =newVodeDode;} else {VodeDode<T> temp = head; head = newVodeDode; head.setNext(temp);} size++;} public T removeBegin() { if(this.head == null) { return null;} else {T current = head.getData(); if (tail == head) { tail = null; head = null; } else { head = head.getNext(); head.setPrev(null);}size--; return current;}} public T getEnd() { if (tail != null) { return tail.getData(); } else { return null;}} public void addEnd(T value) { VodeDode<T> newVodeDode = new VodeDode<T>(value); if (this.tail == null) { head = newVodeDode; tail = newVodeDode; } else { newVodeDode.setPrev(tail); tail.setNext(newVodeDode); tail = newVodeDode;} size++;} public T removeEnd() { if(this.tail == null) { return null;} else { T current = tail.getData();//was head. if (head == tail) { head = null; tail = null; } else { tail = tail.getPrev(); tail.setNext(null);} size--; return current;}} public T removeBN(T value) { VodeDode<T> currVodeDode = head; VodeDode<T> prevVodeDode = null; while(currVodeDode != null){ if(currVodeDode.getData().equals(value)){ if(prevVodeDode != null){ prevVodeDode.setNext(currVodeDode.getNext());} else{ head = curr.

Assignment isPage 349-350 #4 and #5 Use the Linked List lab.pdf

fortmdu

Assignment is: \"Page 349-350 #4 and #5 Use the \"Linked List lab\" you have been working on in class and add the two functions the questions are asking you to develop: divideMid and divideAt. Be sure to include comments Use meaningful identifier names (constants where appropriate) Turn in .cpp file AND Turn in a \"print-screen\' of your output (press \"print-screen\' on keyboard, then \'paste\' in MS-Word)\" How do you solve QUESTION #4 in the book data structures using c++ by D.S. Malik in Visiual Studios using the linked list below with what is being asked? Please need help Linked list : #include #include using namespace std; struct nodeType { int info; nodeType *link; }; void createList(nodeType*& first, nodeType*& last); void printList(nodeType*& first); void insertFront(nodeType*& first); void insertBack(nodeType*& last); void deleteFirst(nodeType*& first); void deleteLast(nodeType*& last, nodeType* first); int main() { nodeType *first, *last; int num; createList(first, last); int choice; while(true) { cout<<\"1. Insert Front.\ 2. Insert Last.\ 3. Delete Front.\ 4. Delete Last.\ 5. Print List.\ 6. Exit.\ \"; cout<<\"Enter your choice: \"; cin>>choice; switch(choice) { case 1: insertFront(first); break; case 2: insertBack(last); break; case 3: deleteFirst(first); break; case 4: deleteLast(last, first); break; case 5: printList(first); break; case 6: return 0; default: cout<<\"Invalid menu option. Try again.\"<>number; while (number != -999) { newNode = new nodeType; // create new node newNode->info = number; newNode->link = NULL; if (first == NULL) { first = newNode; last = newNode; } else { last->link = newNode; last = newNode; } cout<<\"Enter an integer (-999 to stop): \"; cin>>number; } // end of while-loop } // end of build list function void deleteFirst(nodeType*& first) { nodeType *temp; temp= first; first= temp->link; delete temp; return; } void deleteLast(nodeType*& last, nodeType* current) { nodeType *temp; while(current->link != NULL) { temp=current; current=current->link; } temp=last; current->link=NULL; delete temp; last = current; return; } void insertFront(nodeType*& front) { int num; cout<<\"\ Enter the number to insert: \"; cin>>num; nodeType *newNode = new nodeType; newNode->info=num; newNode->link= front; front= newNode; return; } void insertBack(nodeType*& last) { int num; cout<<\"\ Enter the number to insert: \"; cin>>num; nodeType *newNode = new nodeType; newNode->info=num; newNode->link= NULL; last->link= newNode; last = newNode; return; } void printList(nodeType*& first) { cout<<\"Inside printList...printing linked list...\ \"<info << \" \"; current = current->link; } cout< #include using namespace std; struct nodeType { int info; nodeType *link; }; void createList(nodeType*& first, nodeType*& last); void printList(nodeType*& first); void insertFront(nodeType*& first); void insertBack(nodeType*& last); void deleteFirst(nodeType*& first); void deleteLast(nodeType*& last, nodeType* first); int main() { nodeType *firs.

C++: Constructor, Copy Constructor and Assignment operator

Jussi Pohjolainen

pleaase I want manual solution forData Structures and Algorithm An.pdf

wasemanivytreenrco51

pleaase I want manual solution for Data Structures and Algorithm Analysis in C++, Third Edition By Clifford A. Shaffer because my question from this book.page270 ,question 7.4 The implementation for Mergesort given in Section 7.4 takes an array as input and sorts that array. At the beginning of Section 7.4 there is a simple pseudocode implementation for sorting a linked list using Mergesort. Implement both a linked list-based version of Mergesort and the array-based version of Mergesort, and compare and analyze their running times. Solution Linked list: #include #include struct node { int data; struct node* next; }; struct node* SortedMerge(struct node* a, struct node* b); void FrontBackSplit(struct node* source, struct node** frontRef, struct node** backRef); void MergeSort(struct node** headRef) { struct node* head = *headRef; struct node* a; struct node* b; if ((head == NULL) || (head->next == NULL)) { return; } FrontBackSplit(head, &a, &b); MergeSort(&a); MergeSort(&b); *headRef = SortedMerge(a, b); } struct node* SortedMerge(struct node* a, struct node* b) { struct node* result = NULL; if (a == NULL) return(b); else if (b==NULL) return(a); if (a->data <= b->data) { result = a; result->next = SortedMerge(a->next, b); } else { result = b; result->next = SortedMerge(a, b->next); } return(result); } void FrontBackSplit(struct node* source, struct node** frontRef, struct node** backRef) { struct node* fast; struct node* slow; if (source==NULL || source->next==NULL) { *frontRef = source; *backRef = NULL; } else { slow = source; fast = source->next; while (fast != NULL) { fast = fast->next; if (fast != NULL) { slow = slow->next; fast = fast->next; } } *frontRef = source; *backRef = slow->next; slow->next = NULL; } } void printList(struct node *node) { while(node!=NULL) { printf(\"%d \", node->data); node = node->next; } } void push(struct node** head_ref, int new_data) { struct node* new_node = (struct node*) malloc(sizeof(struct node)); new_node->data = new_data; new_node->next = (*head_ref); (*head_ref) = new_node; } int main() { struct node* res = NULL; struct node* a = NULL; push(&a, 15); push(&a, 10); push(&a, 5); push(&a, 20); push(&a, 3); push(&a, 2); MergeSort(&a); printf(\"\ Sorted Linked List is: \ \"); printList(a); getchar(); return 0; } Time complexity:o(nlogn) Array : #include #include void merge(int arr[], int l, int m, int r) { int i, j, k; int n1 = m - l + 1; int n2 = r - m; int L[n1], R[n2]; for (i = 0; i < n1; i++) L[i] = arr[l + i]; for (j = 0; j < n2; j++) R[j] = arr[m + 1+ j]; i = 0; // Initial index of first subarray j = 0; k = l; while (i < n1 && j < n2) { if (L[i] <= R[j]) { arr[k] = L[i]; i++; } else { arr[k] = R[j]; j++; } k++; } while (i < n1) { arr[k] = L[i]; i++; k++; } while (j < n2) { arr[k] = R[j]; j++; k++; } } void mergeSort(int arr[], int l, int r) { if (l < r) { int m = l+(r-l)/2; // Sort first and second halves mergeSort(arr, l, m); mergeSort(arr, m+1, r); merge(arr, l, m, r); } } void printArray(int A[], i.

How do you stop infinite loop Because I believe that it is making a.pdf

feelinggift

How do you stop infinite loop? Because I believe that it is making an infinite circular list. c++ code: Here is the list class: #ifndef LIN_J_LIST #define LIN_J_LIST typedef unsigned int uint; #include #include using namespace std; /** * a simplified generic singly linked list class to illustrate C++ concepts * @author Jerry Lin * @version 2/17/17 */ template< typename Object > class List { private: /** * A class to store data and provide a link to the next node in the list */ class Node { public: /** * The constructor * @param data the data to be stored in this node */ explicit Node( const Object & data ) : data{ data }, next{ nullptr } {} Object data; Node * next; }; public: /** * The constructor for an empty list */ List() : size{ 0 }, first{ nullptr }, last{ nullptr } {} /** * the copy constructor-creates and copy the list */ List( List && rhs ) = delete; List( const List & rhs ) { count = 0; size = 0; if(rhs.size != 0) { push_front(rhs.front()); Node * current = rhs.first; Node * tempNode = first; size++; while(current->next != nullptr) { current = current->next; Node *newNode = new Node(current->data); //transfer the data. basic op. count++; tempNode->next = newNode; last = newNode; tempNode = tempNode->next; size++; } } // you document and implement this method } /** * the operator= method-copies the list */ List & operator=( List && rhs) = delete; List & operator=( const List & rhs ) { count = 0; size = 0; if( size != 0 ) { Node * current = first; Node * temp; while( current != nullptr ) { temp = current; current = current->next; delete temp; } } if(rhs.size!= 0) { push_front(rhs.front()); Node * current = rhs.first; Node * tempNode = first; //create a temporary to store size++; while(current -> next != nullptr) { current = current->next; Node *newNode = new Node(current->data); //transfer the data. basic op count++; tempNode->next = newNode; last = newNode; tempNode = tempNode -> next; size++; } } return *this; // you document and implement this method } /** * accessor * @return count */ int get_count() const { return count; } /** * The destructor that gets rid of everything that\'s in the list and * resets it to empty. If the list is already empty, do nothing. */ ~List() { if( size != 0 ) { Node * current = first; Node * temp; while( current != nullptr ) { temp = current; current = current->next; delete temp; } } } /** * Put a new element onto the beginning of the list * @param item the data the new element will contain */ void push_front( const Object& item ) { Node * new_node = new Node( item );//basic op. if(is_empty()) { last = new_node; } else { new_node->next = first; } first = new_node; size++; /* you complete the rest */ } /** * Remove the element that\'s at the front of the list. Causes an * assertion error if the list is empty. */ void pop_front() { assert( !is_empty() ); Node * temp = first; if( first == last ) { first = last = nullptr; } else { first = first->next; } delete temp; size--; } /** * Accessor to return the da.

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can you add a delete button and a add button to the below program. j.pdf

sales88

The document describes a Java program that implements a linked list of Car objects. It includes classes for the Car object with attributes like make, model, year, and color, and a NuLinkedList class that implements basic linked list functionality for adding, removing, and accessing Car elements. The program reads a file of cars into an ArrayList and provides buttons to navigate between cars, displaying the current car details. The request is to add delete and add buttons to allow removing and adding cars to the linked list from the GUI.

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Here is the editable codeSolutionimport java.util.NoSuchEleme.pdf

Doublylinklist

Can you please debug this Thank you in advance! This program is sup.pdf

Rewrite this code so it can use a generic type instead of integers. .pdf

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lab08build.bat@echo offclsset DRIVE_LETTER=1s.docx

So I have this code(StackInAllSocks) and I implemented the method but.pdf

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C++: Constructor, Copy Constructor and Assignment operator

pleaase I want manual solution forData Structures and Algorithm An.pdf

How do you stop infinite loop Because I believe that it is making a.pdf

C Assignment Help

can you add a delete button and a add button to the below program. j.pdf

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Computer notes - Other Database Objectsecomputernotes

computer notes - Data Structures - 28

The document discusses equivalence relations and the union-find algorithm. It defines what makes a binary relation an equivalence relation by having the properties of reflexivity, symmetry, and transitivity. It gives examples like electrical connectivity being an equivalence relation. The union-find algorithm can be used to dynamically determine if elements are in the same equivalence class based on the given relations, by performing find and union operations in time proportional to m+n for m finds and n-1 unions.

computer notes - Data Structures - 31

computer notes - Data Structures - 4

The document discusses different types of linked lists, including singly linked lists, doubly linked lists, and circularly linked lists. It provides code examples for implementing linked lists in C++ and compares the time complexity of different linked list operations. It also describes how a circularly linked list can be used to solve the Josephus problem of eliminating people seated in a circle.

computer notes - Data Structures - 13

The document discusses binary search trees and different ways to traverse them. It explains that traversing a binary search tree can be done in preorder, inorder, or postorder fashion by recursively visiting the left child, then the node, then the right child in different orders. Searching for a value in a balanced binary search tree takes O(log n) time, while searching an unsorted linked list takes O(n) time.

Computer notes - Advanced Subqueriesecomputernotes

Computer notes - Aggregating Data Using Group Functionsecomputernotes

computer notes - Data Structures - 22

The document discusses deletion in AVL trees and outlines 5 cases to consider when deleting nodes from an AVL tree. It also discusses expression trees and parse trees, providing examples of an expression tree for a mathematical expression and a parse tree for an SQL query. Other uses of binary trees mentioned include their use in compilers for expression trees, parse trees, and abstract syntax trees.

computer notes - Data Structures - 35

The document discusses various data structures including skip lists, AVL trees, and hashing. It explains that skip lists allow for logarithmic-time operations and are simple to implement. Hashing provides constant-time operations by mapping keys to array indices via a hash function, but collisions must be handled. Common hash functions discussed include summing character codes or converting to a number in a prime base.

Computer notes - Enhancements to the GROUP BY Clauseecomputernotes

Computer notes - Manipulating Dataecomputernotes

Computer notes - Writing Basic SQL SELECT Statementsecomputernotes

computer notes - Data Structures - 14

The document discusses recursion and different traversal methods for binary trees. It explains how the call stack is used during recursive function calls and shows examples of preorder and inorder recursive tree traversals. It then describes how to perform non-recursive inorder traversal using an explicit stack. Finally, it introduces level-order traversal, which visits all nodes at each level from left to right before proceeding to the next level.

computer notes - Data Structures - 10